[데이터 과학을 위한 파이썬 프로그래밍]연습문제 4장.< 조건문과 반복문 >

 
#1.
def calculator(N):
    # 짝수
    if N % 2 == 0:
        result = 1
        for i in range(1, N+1):
            result = result * i
            
    # 홀수        
    else: 
        result = 0
        for i in range(1, N+1):
            result = result + i
            
    return result
 
calculator(2) # 1*1*2 = 2
calculator(3) # 0+1+2 = 3
calculator(4) # 1*1*2*3*4 = 24
calculator(5) # 0+1+2+3+4+5= 15
 
for i in range(1, 3):
    print(i)
    
    
    
#2.
    
fruit = 'apple'
if fruit == 'Apple':
    fruit = 'Apple'
elif fruit == 'fruit':
    fruit = 'fruit'
else:
    fruit = fruit
print(fruit)
 
 
#3.
#1 
num = ['12', '34', '56']
for i in num:
    i = int(i)
print(num)
 
 
int(12)
# 
num = ['12', '34', '56']
for i in range(0,3):
    num[i] = int(i)
print(num)
 
 
# 4
number = ["1", 2, 3, float(4), str(5)]
if number[4] == 5:
    print(type(number[0]))
elif number[3] == 4:
    print(number[2:-1])
    
    
# 5
num = 0
i = 1
 
while i < 8:
    if i % 3 == 0:
        break
    i += 1   # 2,3,4,5,6,7,8,9
    num += i   # 2,5,    9,14,20,27
print(num)##
 
 
# 6
result = 0
for i in range(5, -5, -2): # 5,3,1,-1,-3
    if i < -3:
        result += 1
    else:
        result -= 1
# 0-1 -1 -1 -1 -1 = -5
print(result)
-3 <-3
 
for i in range(5, -5, -2):
    print(i)
    
    
#7.
    
 
#8
 
first_value = 0
second_value = 0
for i in range(1, 10):
    if i is 5:
        continue
        first_value = i
    if i is 10:
        break
        second_value = i
        
print(first_value + second_value)
##
1 is 5
 
first_value = 0
second_value = 0
for i in range(1, 10):
    if i is 5:continue
    first_value = i
    if i is 10:break
    second_value = i
        
print(first_value + second_value)
 
first_value = 0
second_value = 0
for i in range(1, 10):
    if i is 5:
        continue
        first_value = i
    if i is 10:
        break
    second_value = i
        
print(first_value + second_value)
##
 
# 9
num = ""
for i in range(10):
    if i <= 5 and (i % 2)==0:
        continue
    elif i is 7 or i is 10:
        continue
    else:
        num =str(i) + num
        
print(num)
 
 
type(num) # 
 
n = str(5)+str(3)+str(1) +""
print(n)
 
#10.
def work_status(task,worker,day):
    rest_task = task
    for k in range(day):
        if rest_task > 0:
            rest_task = rest_task-worker
        elif rest_task <= 0:
            print("Task end")
    if rest_task > 0:
        print("Hire more workers")
        
work_status(100, 11, 10)
work_status(100, 1, 10)
work_status(100, 9, 10)
work_status(100, 10, 10)
 
#11.
 
score_list = [5, 10, 15, 20, 25, 30]
 
sum_of_score = 0
i = 0
while i <len(score_list) :
    if i % 2 ==0:
        sum_of_score += score_list[i]
    i += 1
    
print(sum_of_score)
 
 
#12.
 
coupon =0
money = 200000
coffee = 3500
while money > coffee:
    if coupon < 4:
        money = money - coffee
        coupon += 1
    else:
        money += 2800
        coupon =0
print(money)
 
# 13.****** 결과값이 맞지 않는 이유를 쓰고 올바르게 나오도록 코드 수정하라.
# (a,b의 숫자와 바릿수가 같으면 스트라이크 / 숫자는 서로 포함하나 자릿수가 다르면 볼.)
 
 
a = "369"
b = "693"
 
strike = 0
ball = 0
 
for num ber in a:
    if b.count(number) > 1:
        if b.find(number) != a.find(number):
            strike += 1
        else:
            ball += 1
            
print("Strike:", strike, "Ball:", ball)
 
 
 
a = "369"
b = "697"
 
strike = 0
ball = 0
 
for number in a:
    if a.count(number) >= b.count(number) or a.count(number) < b.count(number):
        if b.find(number) != a.find(number):
            ball += 1
        else:
            strike += 1
            
print("Strike:", strike, "Ball:", ball)
 
#
a = "369"
b = "967"
 
strike = 0
ball = 0
 
for number in a:
    if b.count(number) >= 1:
        if b.find(number) != a.find(number):
            ball += 1
        else:
            strike += 1
            
print("Strike:", strike, "Ball:", ball)
 
 
for number in a:
    print(b.count(number))
 
print(b.find('3'))
 
 
# 수정된 코드 
a = "369"
b = "379"
 
strike = 0
ball = 0
 
for number in a:
    if b.count(number) >= 1: # 첫번째 if문이 모든 for문에서 1보다 크지 않아 다음 코드로 넘어갈 수 없으므로 수정
        if b.find(number) != a.find(number):
            ball += 1  #--- strike += 1 대신 ---
        else:
            strike += 1   #--- ball += 1 대신 ---
            
print("Strike:", strike, "Ball:", ball)
 
 
# 14.
list_data_a = [1,2]
 
list_data_b = [3,4]
 
for i in list_data_a:
    for j in list_data_b:
        result = i + j
print(result)
 
#15
list_1 = [[1,2], [3], [4,5,6]]
a,b,c = list_1
list_2 = a + b + c
 
print(list_2)